A large number of water drops, each of radius r, combine to have a drop of radius R. If the surface tension is T and mechanical equivalent of heat is J, the rise in heat energy per unit volume will be:

Question

Infinity Learn · Accepted Answer

Conserving volume,  $$N43$$$$π$$$$r3=43$$$$π$$$$R3$$ ⇒$$R3=Nr3Loss$$ of surface energy $$=$$  $$Ui-Uf=TAf-TAi=N4$$$$π$$$$r2T$$−$$4$$$$π$$$$R2T$$ ⇒ heat produced  $$=4$$$$π$$$$TJNr2$$−$$R2$$⇒ heat produced per unit volume $$=4$$$$π$$$$TNr2$$−$$R243$$$$π$$$$R3$$ J $$=3TJNr2R3$$−$$1R=3TJ1r$$−$$1R$$

A large number of water drops, each of radius r, combine to have a drop of radius R. If the surface tension is T and mechanical equivalent of heat is J, the rise in heat energy per unit volume will be:

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