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Q.

A large sheet of charge having charge density ‘p’ coul/m2 passes through a cube having length of side ‘l’. Then maximum electric flux over the surface of the cube is

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a

2σl2∈o

b

σl22∈o

c

2σl2∈o

d

22σl2∈o

answer is A.

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Detailed Solution

Maximum area of the plane enclosed by the cube = area of the plane ADGF = 2l ×l=2l2∴ maximum charge enclosed by the cube = 2l2×σ coul.∴ϕEmax=Qmax/∈0=2σl2∈0.
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