A large tank is filled with water to a height H. A small hole is made at the base of the tank. It takes T1 time to decrease the height of water Hη(η>1); and it takes T2 time to take out the rest of water. If T1 = T2, then the value of η is
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a
2
b
3
c
4
d
22
answer is C.
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Detailed Solution
t = Aa2g[H1-H2]Now, T1 = Aa2g[H-Hη]and T2= Aa2g[Hη-0]According to problem T1 = T2∴ H-Hη = Hη-0 ⇒ H = 2Hη ⇒ η = 4