A large tank filled with water to a height i, is to be emptied through a small hole at the bottom. The ratio of time taken for the level to fall from h to h / 2 and that taken for the level to fall from h / 2 to 0 is
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a
2
b
1/2
c
(2−1)
d
1/(2−1)
answer is C.
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Detailed Solution
we know that ∝H1−H2∴ t1∝[h−(h/2)] and t2∝[(h/2)−0] ∴ t1t2=1−1/21/2=(2−1)