First slide

X-rays

Question

The largest distance between the interatomic planes of a crystal is 2 x $10^{- 7}$ cm. The upper limit for the wavelength of X-rays which can be usefully studied with this crystal is

Easy

A

1 Å
B

2 Å
C

40 Å
D

20 Å

Solution

Bragg's law, $2 dsinθ = nλ or λ = \frac{2 dsinθ}{n}$
For maximum wavelength, $n_{\min} = 1, {(sinθ)}_{\max} = 1$
$∴ λ_{\max} = 2 d or λ_{\max} = 4 \times 10^{- 7} cm = 40 Å$

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