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An LCR circuit contains resistance of 100Ω and a supply of 200 V at 300 rad angular frequency. If only capacitance is taken out from the circuit and the rest of the circuit is joined, current lags behind the voltage by 600. If, on the other hand, only inductor is taken out, the current leads by 600 with the applied voltage. The current flowing in the circuit is

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1 A
1.5 A
2 A
2.5 A

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detailed solution

Correct option is C

According to the given question,tan 600=ωLR and tan 600=1/ωCR∴ ωL=1/ωCcase of resonanceNow Z=R2+ωL-1ωC2=100Ω∴Irms=ErmsZ=200 V100 Ω=2 A

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