An LCR series circuit with a resistance of 100 ohm is connected to an ac source of 200 V (r.m.s.) and angular frequency 300 rad/s. When only the capacitor is removed, the current lags behind the voltage by 60o . When only the inductor is removed the current leads the voltage by 60o. The average power dissipated is

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50 W

100 W

200 W

400 W

answer is D.

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Detailed Solution

tanφ=XLR=XCR⇒tan60o=XLR=XCR⇒XL=XC=3 Ri.e. Z=R2+(XL−XC)2=RSo average power P=V2R=200×200100=400W

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