A lead sphere of mass m falls in a viscous liquid with a terminal velocity v0. Another lead sphere of mass 8 m will fall through the same liquid with a terminal velocity
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a
V0
b
4V0
c
8v0
d
64v0
answer is B.
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Detailed Solution
Terminal velocity vT∝r2 For second lead sphere mass becomes g times i.e., radius becomes two times m=(4/3)πr3ρ ∴ Terminal velocity becomes (2)2v0=4v0.
A lead sphere of mass m falls in a viscous liquid with a terminal velocity v0. Another lead sphere of mass 8 m will fall through the same liquid with a terminal velocity