First slide

Accuracy; precision of instruments and errors in measurements

Question

The least count of a stop watch is $0.2 s$ . The time of 20 oscillations of a pendulum is measure to be $25 s$ . The percentage error in the time period is

Moderate

A

1.2%
B

0.8%
C

1.8%
D

None of these

Solution

$T = \frac{t}{n} Δ T = \frac{Δ t}{n} \frac{Δ T}{T} \times 100 = \frac{Δ t}{t} \times 100 = \frac{0.2}{25} \times 100 = 0.8 %$

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