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The least count of a stop watch is 0.2 s. The time of 20 oscillations of a pendulum is measure to be 25 s. The percentage error in the time period is

a
1.2%
b
0.8%
c
1.8%
d
None of these

detailed solution

Correct option is B

T=tn ΔT=Δtn ΔTT×100=Δtt×100 =0.225×100 =0.8%

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