Length AB of the wedge shown in figure is rough and BC is smooth. A solid cylinder rolls without slipping from A to B. If AB=BC, then ratio of translational kinetic energy to rotational kinetic energy when the cylinder reaches point C is :
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a
3/5
b
5
c
7/5
d
8/3
answer is B.
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Detailed Solution
For a cylinder if Kr is translational KE and KR is rotational KEin case of pure rolling upto B: and After B: Rotational kinetic energy is constant however transitional kinetic energy increases.At C: while Alternative solution:For journey from A to B, conserving energy we can write For solid cyliner, At B, rotational K.E, Also for journey from B to C, loss in P.E. is converted into additional translational K.E. so KET at C =