The length, breadth and thickness of a rectangular sheet of metal are 4.234 m, 1.005 m and 2.01 cm respectively. The area and volume of the sheet to correct significant figures are
Given, length (l) = 4.234 m
Breadth (b) =1.005 m
Thickness (t) =2.01cm =0.0201m
Area of sheet (A)
As thickness has least number of significant figures 3, therefore rounding-off area up to three significant figures, we get
Area of sheet
Volume of sheet (V) = l b t
= 0.0855289
Rounding-off up to three significant figures, we get Volume of the sheet