The length, breadth and thickness of a rectangular sheet of metal are 4.234 m, 1.005 m and 2.01 cm respectively. The area and volume of the sheet to correct significant figures are

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8.72 m2 and 0.0855 m3

8.7 m2 and 0.085 m3

0.87 m2 and 0.855 m3

0.087 m2 and 0.0855 m3

answer is A.

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Detailed Solution

Given, length (l) = 4.234 mBreadth (b) =1.005 mThickness (t) =2.01cm =0.0201mArea of sheet (A)=2(ℓ×b+b×t+t×ℓ)=2[(4.234×1.005)+(1.005×0.0201)+(0.020×4.234)]=2×43604739=8.7209478 m2As thickness has least number of significant figures 3, therefore rounding-off area up to three significant figures, we getArea of sheet (A)=8.72 m2Volume of sheet (V) = l × b × t=4.234×1.005×0.0201= 0.0855289Rounding-off up to three significant figures, we get Volume of the sheet=0.0855 m3

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