Length of a closed pipe is $$75$$ cm. First overtone of this closed pipe beats with the first over tone of an open pipe with a beat frequency of $$5$$ Hz. If velocity of sound in air is $$330$$ Hz, what is the length of the open pipe ?

Question

Infinity Learn · Accepted Answer

First overtone of closed pipe $$=$$ $$(f1)CFirst$$ overtone of open pipe $$=$$ $$(f1)0f1C$$ $$=$$  $$3$$  .  $$V4lC$$ $$=$$  $$3$$ × $$3304$$  ×  $$0.75$$  Hz  $$=$$  $$330$$  $$Hzf10$$ $$=$$  $$4$$  .  $$V4l0$$ $$=$$   $$330l0$$ . HzNow   $$330l0$$ − $$330$$ $$=5$$  ⇒  $$l0$$ $$=$$ $$0.985$$  $$m=98.5$$  cm.Again,  $$330$$ −  $$330l0$$  $$=5$$  ⇒  $$l0$$ $$=$$ $$1.015$$  $$m=101.5$$  cm.

Length of a closed pipe is 75 cm. First overtone of this closed pipe beats with the first over tone of an open pipe with a beat frequency of 5 Hz. If velocity of sound in air is 330 Hz, what is the length of the open pipe ?

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