Questions
The length of the compound microscope is 14 cm. The magnifying power for relaxed eye is 25. If the focal length of eye lens is 5 cm, then the object distance for objective lens will be
a
1.8 cm
b
1.5 cm
c
2.1 cm
d
2.4 cm
detailed solution
Correct option is A
L∞=vo+fe⇒14=vo+5⇒vo=9cmMagnifying power of microscope for relaxed eyem=vouo.Dfe or 25=9uo.255 or uo=95=1.8 cmTalk to our academic expert!
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