The length of each rail is 10m. The linear expansion of steel is 0.000012/0C and the range of variation of temperature at the given place is 150C. So the gap to be provided between the rail is
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a
0.0018m
b
0.0012m
c
0.0022m
d
0.02m
answer is A.
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Detailed Solution
change in length due to variation in temperature is Δl=lαΔt here l is initial length=10m;α is coefficient of linear expansion=12×10−6/C 0 Δt is change in temperature=150C Δl=10×12×10−6×15 Δl=180×10−5=18×10−4 Δl=0.0018m=gap between 2 rails to be maintained