Q.

The length of each rail is 10m. The linear expansion of steel is 0.000012/0C and the range of variation of temperature at the given place is 150C. So the gap to be provided between the rail is

Moderate

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0.0018m

0.0012m

0.0022m

0.02m

answer is 1.

(Detailed Solution Below)

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Detailed Solution

change in length due to variation in temperature is Δl=lαΔt here l is initial length=10m;α is coefficient of linear expansion=12×10−6/C 0 Δt is change in temperature=150C Δl=10×12×10−6×15 Δl=180×10−5=18×10−4 Δl=0.0018m=gap between 2 rails to be maintained

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