Questions

# The length of each rail is 10m. The linear expansion of steel is  $0.000012{/}^{0}C$ and the range of variation of temperature at the given place is  ${15}^{0}C$. So the gap to be provided between the rail is

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a
0.0018m
b
0.0012m
c
0.0022m
d
0.02m
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detailed solution

Correct option is A

change in length due to variation in temperature is Δl=lαΔt here l is initial length=10m;α is coefficient of linear expansion=12×10−6/C  0 Δt is change in temperature=150C Δl=10×12×10−6×15 Δl=180×10−5=18×10−4 Δl=0.0018m=gap between 2 rails to be maintained

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