The length of each side of a cubical closed surface is l. If charge q is situated on one of the vertices of the cube, then the flux passing through each face of the cube will be
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a
q6ε0
b
q12ε0
c
q24ε0
d
q16ε0
answer is C.
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Detailed Solution
The charge contributes only (q/8)th to this cube. Further, these faces of the cube meet at one corner which are parallel to the charge. From Gauss theoremΦone face =(q/8)3ε0=q24ε0