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Questions  

The length of an elastic string is a meter when the longitudinal tension is 4N and b meter when the longitudinal tension is 5N . The original length of the string in meter is

a
a−b
b
5a-4b
c
2b−14a
d
4a−3b

detailed solution

Correct option is B

Using Hooke’s law, F=Kx we can write 4=k(a−ℓ0)  …. (i)and 5=k(b−ℓ0)  …. (ii)divide (1) by (2)45=k(a−ℓ0)k(b−ℓ0)⇒4b-4ℓ0=5a-5ℓ0⇒ℓ0=5a-4b

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