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The length of germanium rod is 2 cm and its area of cross section is 2 mm2. If for germanium ni=2.5x1019m-3 , μe=0.39m2v-1s-1, μh=0.19m2v-1s-1. Its resistance in ohms is

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answer is 4310.34Ω.

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Detailed Solution

Resistance=R =ρlA=1σlA =lnie(μe+μh)A =2×10−22.5×1019×1.6×10−19(0.39+0.19)2×10−6 =4310.34Ω

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