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The length of germanium rod is 1 cm and its area of cross-section is 1mm2. If for germanium ni=2.5×1019m−3 , μe=0.39m2v−1s−1 , μh=0.19m2v−1s−1. Its resistance in ohms is

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answer is 4310.34.

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Detailed Solution

Resistance = R=ρlA=lnieμe+μhA=1×10−22.5×1019×1.6×10−190.39+0.19×10−6 =4310.34 Ω

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The length of germanium rod is 1 cm and its area of cross-section is 1mm2. If for germanium ni=2.5×1019m−3 , μe=0.39m2v−1s−1 , μh=0.19m2v−1s−1. Its resistance in ohms is