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The length of a germanium rod is 0.58 cm and its area of cross-section is 1 mm². if for Germanium $n_{i} = 2 \cdot 5 \times 10^{19} m^{- 3}, μ_{h} = 0 \cdot 19 m^{2} / V - s$ $μ_{e} = 0 \cdot 9 m^{2} / V - s$ , then the resistance of the rod will be

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detailed solution

Correct option is A

R=ρLA=Lnieμe+μhA =0⋅58×10−22⋅5×10191⋅6×10−19[0⋅19+0⋅39]×1×10−6 =2⋅5kΩ

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The length of a germanium rod is 0.58 cm and its area of cross-section is 1 mm2. if for Germaniumni=2⋅5×1019m−3,μh=0⋅19m2/V−s μe=0⋅9m2/V−s, then the resistance of the rod will be

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Ready to Test Your Skills?

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The length of a germanium rod is 0.58 cm and its area of cross-section is 1 mm². if for Germanium $n_{i} = 2 \cdot 5 \times 10^{19} m^{- 3}, μ_{h} = 0 \cdot 19 m^{2} / V - s$ $μ_{e} = 0 \cdot 9 m^{2} / V - s$ , then the resistance of the rod will be