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Q.

The length of a germanium rod is 0.58 cm and its area of cross-section is 1 mm2. if for Germaniumni=2⋅5×1019m−3,μh=0⋅19m2/V−s μe=0⋅9m2/V−s, then the resistance of the rod will be

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a

2⋅5kΩ

b

5⋅0kΩ

c

7⋅5kΩ

d

10kΩ

answer is A.

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Detailed Solution

R=ρLA=Lnieμe+μhA =0⋅58×10−22⋅5×10191⋅6×10−19[0⋅19+0⋅39]×1×10−6 =2⋅5kΩ
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