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The length of a given cylindrical wire is increased by 100%. Due to the consequent decrease in diameter the change in the resistance of the wire will be
detailed solution
Correct option is A
If initial length l1 = 100, thenl2 = 100 + 100 = 200R1R2 = l1l22 = 1002002 ⇒ R2 =4R1ΔRR×100=R2−R1R1 ×100 = R1−R1R1 ×100 =300%Talk to our academic expert!
Similar Questions
In an electrical cable there is a single wire of radius 9 mm of copper. Its resistance is 5Ω . The cable is replaced by 6 different insulated copper wires, the radius of each wire is 3 mm . Now the total resistance of the cable will be
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