Q.
Length of a hollow tube is 5 m, its outer diameter is 10 cm and thickness of its wall is 5 mm. If resistivity of the material of the tube is 1.7×10−8Ωm then resistance of tube will be
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a
5.6×10−5Ω
b
2×10−5Ω
c
4×10−5Ω
d
None of these
answer is A.
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Detailed Solution
By using R=ρ. lA; here A=πr22−r12Outer radius r2=5 cmInner radius r1=5−0.5 = 4.5 cmSo R=1.7 × 10−8 × 5π5 × 10−22 − 4.5 × 10−22=5.6 × 10−5 Ω
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