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Q.

Length of a hollow tube is 5 m, its outer diameter is 10 cm and thickness of its wall is 5 mm. If resistivity of the material of the tube is 1.7×10−8Ωm  then resistance of tube will be

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a

5.6×10−5Ω

b

2×10−5Ω

c

4×10−5Ω

d

None of these

answer is A.

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Detailed Solution

By  using  R=ρ. lA; here  A=πr22−r12Outer  radius r2=5  cmInner  radius  r1=5−0.5  =  4.5  cmSo  R=1.7  ×  10−8 ×  5π5 ×  10−22 − 4.5 ×  10−22=5.6 ×  10−5 Ω
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