The length l, breadth b, and thickness t, of a block of wood were measured with the help of a measuring scale. The results with permissible errors (in cm) arel=15.12±0.01,b=10.15±0.01, and t=5.28±0.01. The percentage error in volume up to proper significant figures is
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a
0.28%
b
0.35%
c
0.48%
d
0.64%
answer is B.
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Detailed Solution
Percentage error in volume since V=Lbt ⇒∆VV×100=∆LL×100+∆bb×100+∆tt×1000.0115.12×100+0.0110.15×100+0.015.28×100=0.35%