First slide

Thermal expansion

Question

A length of 2m is measured using a metal tape at 10⁰C. It is calibrated at a temperature 30⁰C. The actual length is (α = 1 x 10^-4/C⁰)

Easy

A

2.004 m
B

1.996 m
C

1.004 m
D

0.004 cm

Solution

Thermal contraction of 2m length = $\large \Delta l=\alpha l(t_2-t_1)=10^{-4}(2)(30-10)=0.004m$
Actual length = 2 - (0.004) = 1.996m

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