The length of a metal wire is l1 when the tension in it is T1 and is l2 when the tension is T2. The natural length of the wire is
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a
I1+l22
b
I1I2
c
I1T2−I2T1T2−T1
d
I1T2+I2T1T2+T1
answer is C.
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Detailed Solution
As, Young's modulus of elasticity, Y= Stress Strain ⇒ Y=T1×LA×I1−L .... (i)where, L is the original length of the wire and alsoY=T2×LA×I2−L …. (ii) From Eqs. (i) and (ii), we getT1LAI1−L=T2LAI2−L⇒L=T2I1−T1I2T2−T1