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The length of metallic wire is $l_{1}$ when tension in it is $T_{1}$ . It is $l_{2}$ when the tension is $T_{2}$ . The original length of the wire will be :

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l1+l22

T2l1−T1l2T2−T1

T1l1−T2l2T2−T1

T2l1+T1l2T1+T2

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detailed solution

Correct option is B

Young Modulus, Y=TlAe ⇒e ∝ T ⇒l1−l0l2−l0=T1T2 ⇒l0=l1T2−l2T1T2−T1`

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The length of metallic wire is l1 when tension in it is T1 . It is l2 when the tension is T2. The original length of the wire will be :

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Ready to Test Your Skills?

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The length of metallic wire is $l_{1}$ when tension in it is $T_{1}$ . It is $l_{2}$ when the tension is $T_{2}$ . The original length of the wire will be :