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Length of a one-metre long uniform spring of mass $5 0.0 g$ increases by $2 .00 cm$ due to its own weight, if it is suspended from a fixed support. How much load should be suspended from the lower end of this spring so that total extensions becomes $1 0.0 cm$ .

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100g

125g

200g

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detailed solution

Correct option is A

mg2K=Δx Mg+mg2K=Δx'm2M+m=210=155m =2M+m4m=2M4(50) =2 MM=100g

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Length of a one-metre long uniform spring of mass 50.0 g increases by 2.00cm due to its own weight, if it is suspended from a fixed support. How much load should be suspended from the lower end of this spring so that total extensions becomes 10.0cm .

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Length of a one-metre long uniform spring of mass $5 0.0 g$ increases by $2 .00 cm$ due to its own weight, if it is suspended from a fixed support. How much load should be suspended from the lower end of this spring so that total extensions becomes $1 0.0 cm$ .