The length of plane mirror is 1cm. The wavelength of source is 5000 A0 . The number of maxima formed on the large screen are (P is central point on screen)
19,999
20,000
20,001
39,998
An image S' will form at 5mm behind the mirror. Hence, Path difference at P = ∆x = S'P - SP = 10 mm Also, ∆x = nλ [Condition for minima, as mirror introduces phase difference of π] ⇒n= ∆xλ=10×10-35×10-7 = 20,000th minima At infinity, ∆x = 0 means minima Hence, between lower Infinity and point P , 19,999 maxima exists. No interference occur above point P.