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The length of potentiometer wire is 100 cm and the emf of its standard cell is E volts. It is employed to measure the emf of a battery whose internal resistance is 0.5 ohm. If the balance point is obtained at l = 30 cm from positive end, the emf of the battery is

a
30E100.5
b
30E100−0.5
c
30E100
d
100E30

detailed solution

Correct option is C

VαI,E'E=30100

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