First slide

Ohm's law

Question

The length of the resistance wire is increased by 10%. What is the corresponding change in the resistance of wire?

Easy

A

10%
B

25%
C

21%
D

9%

Solution

$\begin{array}{l} \frac{R_{2}}{R_{1}} = {(\frac{l_{1}}{l_{2}})}^{2}, If l_{1} = 100 then l_{1} = 110 \\ \Rightarrow \frac{R_{1}}{R_{2}} = {(\frac{100}{110})}^{2} \Rightarrow R_{2} = 1 .21 R_{1} \\ % change \frac{R_{2} - R_{1}}{R_{1}} \times 100 = 21 % \end{array}$

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