First slide
Elastic Modulie
Question

The length of a rod is 20 cm and area of cross-section 2 cm2. The Young's modulus of the material of wire is 1.4×1011 N/m2. If the rod is compressed by 5 kg-wt along its length, then increase in the energy of the rod in joules will be

Moderate
Solution

Energy = 12Fl = 12×F×(FLAY) =12×F2LAY 

          = 12×(50)2×20×10-22×10-4×1.4×1011 = 8.57×10-6 J

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