Questions
The length of the second pendulum on the surface of earth is 1 m. The length of seconds pendulum on the surface of moon, where g is 1/6th value of g on the surface of earth, is
detailed solution
Correct option is A
T=2πlg⇒lg = constant⇒l∝g; ⇒lm1=16gg⇒lm=16mTalk to our academic expert!
Similar Questions
A simple pendulum has time period T1. The point of suspension is now moved upward according to equation where . If new time period is T2 then ratio will be
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