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The length of a simple pendulum is 50 cm and mass of its bob is 0.1 kg. The bob is given a velocity 5 m/s along horizontal direction when the bob is at lowest position and the bob describes vertical circle of radius equal to length of pendulum. The position in the vertical circle, where the tension in the string is 4.5 N is
(g = 10ms–2)

a
highest point
b
lowest point
c
at an angle 600 from lowest point of vertical circle
d
at an angle of 600 from highest point of vertical circle

detailed solution

Correct option is C

Tension at any point T= mv2l-2mg+3mgcosθ where v is the velocity at the lowest point 4.5=0.1520.5-2×10+3×10cosθ 45=50-20+30cosθ 15=30cosθ cosθ=1/2  θ=600  form the lowest point from the top point it is 1800-600=1200

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Similar Questions

A pendulum of length / = l m is released from θ0 = 600. The rate of change of speed of the bob at θ = 300 is (g = 10 m/s2)


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