Questions
The length of a simple pendulum is 50 cm and mass of its bob is 0.1 kg. The bob is given a velocity 5 m/s along horizontal direction when the bob is at lowest position and the bob describes vertical circle of radius equal to length of pendulum. The position in the vertical circle, where the tension in the string is 4.5 N is
(g = 10ms–2)
detailed solution
Correct option is C
Tension at any point T= mv2l-2mg+3mgcosθ where v is the velocity at the lowest point 4.5=0.1520.5-2×10+3×10cosθ 45=50-20+30cosθ 15=30cosθ cosθ=1/2 θ=600 form the lowest point from the top point it is 1800-600=1200Talk to our academic expert!
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A pendulum of length / = l m is released from . The rate of change of speed of the bob at is (g = 10 )
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