First slide

Periodic Motion

Question

The length of a simple pendulum is increased by 44%. What is the percentage increase in its time period?

Easy

A

10%
B

20%
C

40%
D

44%

Solution

$T = 2 π \sqrt{\frac{l}{g}} \Rightarrow \frac{T'}{T} = \sqrt{\frac{l'}{l}} \Rightarrow T' = (\sqrt{1.44}) T = 1.2 T so % increase = 20 %$

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