The length of a simple pendulum is $$1m$$. The bob is given a velocity $$7m/s$$ in horizontal direction from mean position. During upward motion of bob, if the string is burnt when it is horizontal, then the maximum vertical height of ascent of bob from rest position is

Question

Infinity Learn · Accepted Answer

From conservation of energy $$12mv2=12mv12+mgr$$ $$v1is$$ the velocity at the horizontal positon $$v12=v2-2gr$$   From there maximum height is $$v122g=v2-2gr2g=$$ $$v22g-r$$ Therefore total $$height=r+v22g-r$$ $$=722$$×$$9.8$$ $$m=2.5$$ m

The length of a simple pendulum is 1m. The bob is given a velocity 7m/s in horizontal direction from mean position. During upward motion of bob, if the string is burnt when it is horizontal, then the maximum vertical height of ascent of bob from rest position is

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