Q.

The length of a simple pendulum, measured by an instrument of least count 4 mm, is found to be 40 cm. Its time period is measured by taking 200 oscillations using a watch of resolution 2s. The time period of found to be 0.4 s. Find the fractional error in the determination of the acceleration due to gravity using this data.

Moderate

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By Expert Faculty of Sri Chaitanya

answer is 0000.06.

(Detailed Solution Below)

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Detailed Solution

Δℓℓ=0.440 Acceleration due to gravity =g =4π2LT2Δtt=2200×0.4 Now, Δgg=Δℓℓ+2⋅Δtt=0.440+2×2200×0.4=0.06

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