Length of a spring of force constant k in its unstretched condition is l. The spring is cut into two parts which have their unstretched lengths in the ratio $$l1$$:$$l2=q$$:$$1$$. Force constants of the two parts $$k1$$ and $$k2$$ are then:

Question

Length of a spring of force constant k in its unstretched condition is l. The spring is cut into two parts which have their unstretched lengths in the ratio $$l1$$:$$l2=q$$:$$1$$. Force constants of the two parts $$k1$$ and $$k2$$ are then:

Infinity Learn · Accepted Answer

$$l1+l2=l$$ As $$l1=ql2$$∴                              $$l2=lq+1and$$ $$l1=qlq+1$$                                  $$k1=mgl1=mgq+1ql=kq+1q$$                                  $$k2=mgl2=mgl2q+1=kq+1$$

Length of a spring of force constant k in its unstretched condition is l. The spring is cut into two parts which have their unstretched lengths in the ratio $l_{1} : l_{2} = q : 1$ . Force constants of the two parts k₁ and k₂ are then:

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Length of a spring of force constant k in its unstretched condition is l. The spring is cut into two parts which have their unstretched lengths in the ratio l1:l2=q:1. Force constants of the two parts k1 and k2 are then:

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Length of a spring of force constant k in its unstretched condition is l. The spring is cut into two parts which have their unstretched lengths in the ratio $l_{1} : l_{2} = q : 1$ . Force constants of the two parts k₁ and k₂ are then: