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Q.

The length of a spring is l and its force constant is k. When a weight W is suspended from it, its length increases by x. If the spring is cut into two equal parts and put in parallel and the same weight W is suspended from them, then the extension will be

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a

2x

b

x

c

x2

d

x4

answer is D.

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Detailed Solution

Spring is cut into two equal halves so spring constant of each part = 2k These parts are in parallel so Keq=2K+2K=4KExtension force (i.e. W) is same hence by using  F=kx⇒4k×x'=kx⇒x'=x4.
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