Questions
The length of a spring is l and its force constant is k. When a weight W is suspended from it, its length increases by x. If the spring is cut into two equal parts and put in parallel and the same weight W is suspended from them, then the extension will be
detailed solution
Correct option is D
Spring is cut into two equal halves so spring constant of each part = 2k These parts are in parallel so Keq=2K+2K=4KExtension force (i.e. W) is same hence by using F=kx⇒4k×x'=kx⇒x'=x4.Talk to our academic expert!
Similar Questions
An ideal spring with spring-constant K is hung from the ceiling and a block of mass M is attached to its lower end. The mass is released with the spring initially unstretched. Then the maximum extension in the spring is
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