The length of two open organ pipes are l and (l+Δl) respectively. Neglecting end correction, the frequency of beats between them will be approximately(Here v is the speed of sound)
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a
v2l
b
v4l
c
vΔl2l2
d
vΔll
answer is C.
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Detailed Solution
λ1=2l, λ2=2l+2Δl ⇒n1=v2l and n2=v2l+2Δl⇒ No. of beats =n1−n2=v21l−1l+Δl=vΔl2l2