Questions
The length of the wire between two ends of a sonometer is 100 cm. What should be the positions of two bridges below the wire so that the three segments of the wire have their fundamental frequencies in the ratio 1: 3: 5.
detailed solution
Correct option is D
Let L(=100 cm) be the length of the wire and L1,L2 and L3 are the lengths of the segments as shown in the figure. Fundamental frequency, v∝1L As the fundamental frequencies are in the ratio of 1:3 : 5, ∴ L1:L2:L3=11:13:15=15:5:3 Let x be the common factor. Then 15 x+5 x+3 x=L=100 23x=100 or x=10023 ∴ L1=15×10023=150023 cm L2=5×10023=50023 cm L3=3×10023=30023 cm ∴ The bridges should be placed from A at 150023 cm and 200023 cm respectively.Talk to our academic expert!
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Two parts of a sonometer wire divided by a movable bridge differ in length by o ' 2 cm and produce one beat per second, when sounded together. The total lengths of wire is one metre, then the frequencies are
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