A length of wire caries a steady current. First it is bent to form a circular coil of one tum. Then it is bent more sharply to form a loop of two turns but of smaller radius. Now the magnetic flux density at the centre caused by same current is found to be such that
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a
magnetic flux density of double loop = 1/4 that of single turn coil
b
it is four times that of single turn coil
c
it is same and remains unaltered
d
it is one-half of the first value
answer is B.
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Detailed Solution
B =B1=μ0Ni2R L=N×2πR B2=μ02Ni2 R2 L=2N×2πR2 B2=4 B1