Accuracy; precision of instruments and errors in measurements

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The length of a wire is 2.17 cm and radius is 0.46 cm. The number of significant digits in the value of volume of wire is ________________

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Solution

The volume of wire
$\begin{matrix} = π r^{2} l = 3.14 \times (0.46)^{2} \times 2.17 {cm}^{3} \\ = 1.4418 {cm}^{3} = 1.4 {cm}^{3} \end{matrix}$
(The number of significant figures in multiplication or division should equal to minimum number of decimal points of a quantity involved in the operation.)
Thus, number of significant digits in 1.4 cm³ is 2

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Accuracy; precision of instruments and errors in measurements

Remember concepts with our Masterclasses.

The length of a wire is 2.17 cm and radius is 0.46 cm. The number of significant digits in the value of volume of wire is ________________

The volume of wire=πr2l=3.14×(0.46)2×2.17cm3=1.4418cm3=1.4cm3(The number of significant figures in multiplication or division should equal to minimum number of decimal points of a quantity involved in the operation.)Thus, number of significant digits in 1.4 cm3 is 2

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