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Q.

The length of a wire is increased by 1 mm on the application of a given load. In a wire of the same material, but of length and radius twice that of the first, on application of the same load, extension is

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a

0.25 mm

b

0.5 mm

c

2mm

d

4 mm

answer is B.

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Detailed Solution

Y=F/aΔl/l  or  Y=FlaΔl or  Δl=FlaY=Flπr2YIn the given problem,Δl∝lr2When both I and r are doubled, ∆l is halved.Δlnew =0.5mm
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