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Q.

The length of a wire of a potentiometer is 100 cm, and the e.m.f. of its standard cell is E volt. It is employed to measure the e.m.f. of a battery whose internal resistance is 0.5  Ω.  If the balance point is obtained at l = 30 cm from the positive end, the e.m.f. of the battery is

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a

30E100

b

30E100.5

c

30E100−0.5

d

30E−0.5i100,  where i is the current in the potentiometer

answer is A.

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Detailed Solution

From the principle of potentiometet, V  ∝   l⇒  VE  =  lL  ;  where V = emf of battery E = emf of standard cell, L = Length of potentiometer wireV=  ElL  =  30E100
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The length of a wire of a potentiometer is 100 cm, and the e.m.f. of its standard cell is E volt. It is employed to measure the e.m.f. of a battery whose internal resistance is 0.5  Ω.  If the balance point is obtained at l = 30 cm from the positive end, the e.m.f. of the battery is