First slide

potentiometer

Question

The length of a wire of a potentiometer is 100 cm, and the emf of its standard cell is E volt. It is employed to measure the emf of a battery whose internal resistance is 0.5 $Ω$ . If the balance point is obtained at l = 30 cm from the positive end, the emf of the battery is

Moderate

A

$\frac{30 E}{100}$
B

$\frac{30 E}{100.5}$
C

$\frac{30 E}{(100 - 0.5)}$
D

$\frac{30 (E - 0.5 i)}{100}$

Solution

Using the principle of potentiometer, V $\infty$ l. So
$\frac{V}{E} = \frac{l}{L} o r V = \frac{l}{L} E = \frac{30}{100} E = \frac{30 E}{100}$

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