The lengths of an elastic wire are a, b when the tensions in it are 10 N, 20 N respectively. If the tension in the same wire is 40 N then its length is
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a
b-2a
b
3b-2a
c
4b-3a
d
5b-3d
answer is B.
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Detailed Solution
Let c is the length of the wire when the tension in the wire is 40 Nb−ac−b=20−1040−20⇒c=3b−2a