Questions

The lengths and radii of two rods made of same materials are in the ratio of 1:2 and 2:3 respectively, if the temperature difference between the ends for the two rods be the same, then in steady state, the amount of heat flowing through them will be in the ratio

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a

1:3

b

4:3

c

8:9

d

3:2

NEW

detailed solution

Correct option is C

given l1l2=12K=constant= coefficient of thermal conductivityr1r2=23 ( here r is radius of the cross section)Δθ=constant= temperature differenceQ1Q2=?Power P=Qt=KA(θ1-θ2)l=KA∆θl=Kπr2∆θlQtαr2lPαr2lP1P2=r1r22×l2l1P1P2=232×21P1P2=49×21=89 P1P2=89 is ratio of amount of heat flow per second

Similar Questions

Two rods of length ${\mathrm{d}}_{1}$ and ${\mathrm{d}}_{2}$ and coefficients of thermal conductivities ${\mathrm{K}}_{1}$ and ${\mathrm{K}}_{2}$ are kept touching each other. Both have the same area of cross-section. The equivalent of thermal conductivity is

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