The lengths and radii of two rods made of same materials are in the ratio of $$1$$:$$2$$ and $$2$$:$$3$$ respectively, if the temperature difference between the ends for the two rods be the same, then in steady state, the amount of heat flowing through them will be in the ratio

Question

Infinity Learn · Accepted Answer

given $$l1l2=12K=constant=$$ coefficient of thermal $$conductivityr1r2=23$$ $$($$ here r is radius of the cross $$section)$$Δθ$$=constant=$$ temperature $$differenceQ1Q2=$$?Power $$P=Qt=KA($$θ$$1-$$θ$$2)l=KA$$∆θ$$l=K$$$$π$$$$r2$$∆θlQtα$$r2lP$$α$$r2lP1P2=r1r22$$×$$l2l1P1P2=232$$×$$21P1P2=49$$×$$21=89$$ $$P1P2=89$$ is ratio of amount of heat flow per second

The lengths and radii of two rods made of same materials are in the ratio of 1:2 and 2:3 respectively, if the temperature difference between the ends for the two rods be the same, then in steady state, the amount of heat flowing through them will be in the ratio

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