A lens is placed between a source of light and a wall. It forms images of area A1 and A2 on the wall for its two different positions. The area of the source of light is
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a
A1A2
b
A1+A22
c
A1−A22
d
1A1+1A2
answer is A.
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Detailed Solution
Let say the length and breadth of object is a and b .Area of object = a × b In first position of displacement method, Area of Image1 , A1= m1a×m1b → (1)In second position of displacement method, Area of Image2 , A2= m2a×m2b → (2) Multiply equation 1 and 2 A1A2 = (m1m2)2 (ab)2Also, in displcement method , m1m2 = 1 ⇒A1A2 = (ab)2⇒ab =A1A2 ⇒Area of object = A1A2