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Q.

A lens is placed between a source of light and a wall. It forms images of area A1  and A2 on  the wall for its two different positions. The area of the source of light is

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a

A1A2

b

A1+A22

c

A1−A22

d

1A1+1A2

answer is A.

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Detailed Solution

Let say the length and breadth of object is a and b .Area of object  = a × b   In first position of displacement method,   Area of Image1 , A1= m1a×m1b → (1)In second  position of displacement method,   Area of Image2 , A2= m2a×m2b → (2) Multiply equation 1 and 2  A1A2 = (m1m2)2 (ab)2Also, in displcement method , m1m2 = 1   ⇒A1A2 = (ab)2⇒ab  =A1A2 ⇒Area of object = A1A2
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A lens is placed between a source of light and a wall. It forms images of area A1  and A2 on  the wall for its two different positions. The area of the source of light is