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A lens of refractive index n is put in a liquid of refractive index n' of focal length of lens in air to its focal length in liquid will be

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a
−fn'n−1n'−n
b
−fn'−1n'−n
c
−n'n−1fn'−n
d
−fn'nn−n'

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detailed solution

Correct option is A

1f=n−111R1−1R2and  1f'=n−n'n'1R1−1R2∴f'f=n−11×n'n−n'⇒f'=fn'n−1n'−n


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