A lens of refractive index n is put in a liquid of refractive index n' of focal length of lens in air to its focal length in liquid will be

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−fn'n−1n'−n

−fn'−1n'−n

−n'n−1fn'−n

−fn'nn−n'

answer is A.

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Detailed Solution

1f=n−111R1−1R2and 1f'=n−n'n'1R1−1R2∴f'f=n−11×n'n−n'⇒f'=fn'n−1n'−n

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