A lens which has focal length of 4 cm and refractive index of 1.4 is immersed in a liquid of refractive index 1.6, then the focal length will be
– 12.8 cm
32 cm
12.8 cm
– 32 cm
flfa=aμg−1lμg−1⇒fl4=(1.4−1)1.41.6−1⇒fl=−12.8cm