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Let ‘A’ and ‘B’ be two gases and given TAMA=4TBMB  where T is temperature and M is molecular mass. If VA and VB are the rms speed then the ratio VAVB  will be equal to

a
2
b
4
c
1
d
0.5

detailed solution

Correct option is A

root mean square velocity is Vrms=3RTM  ; here R is universal gas constant; T is absolute temperature; M is molecular weight⇒V∝TM Given TAMA=4TBMBconsider ratio of A&BVAVB=TAMATBMBVAVB=4TBMBTBMB=2

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